Edgar J. Kaiser
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                                                Posted:
                            
                                4 years ago                            
                            
                                30 avr. 2022, 10:22 UTC−4                            
                        
                        
                                                    In 2D axial you must use line integrals on the boundaries, because this is where the charge sits. You can check the surface integral checkbox to get integrated charge around the circumference of the respective edge.
    -------------------
    Edgar J. Kaiser
emPhys Physical Technology
www.emphys.com                                                 
                                                
                            In 2D axial you must use line integrals on the boundaries, because this is where the charge sits. You can check the surface integral checkbox to get integrated charge around the circumference of the respective edge.                        
                                                
                                                                                                            
                                             
                                            
                                                
    
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                                                Posted:
                            
                                3 years ago                            
                            
                                1 mai 2022, 07:55 UTC−4                            
                        
                        
                                                    Thank you for your reply!
Yeah it is actually working only for ES Physics but the answer is very small (order 1e-20 F), I'm a bit skeptical of this result. When applying it to EC Physics,  it is giving complex values for the line integration of the surface charge density, which is also unreasonable.
I am thinking that the capacitance in this case is a fixed value C = Q/U. i.e. for each potential applied to all parts of the conductor equally, the charges sitting on each surface will change in a way that keeps the ratio (Q/U) constant. are there any other methods for calculating the stray capacitance in comsol ?
                                                 
                                                
                            Thank you for your reply!
Yeah it is actually working only for ES Physics but the answer is very small (order 1e-20 F), I'm a bit skeptical of this result. When applying it to EC Physics,  it is giving complex values for the line integration of the surface charge density, which is also unreasonable.
I am thinking that the capacitance in this case is a fixed value C = Q/U. i.e. for each potential applied to all parts of the conductor equally, the charges sitting on each surface will change in a way that keeps the ratio (Q/U) constant. are there any other methods for calculating the stray capacitance in comsol ?                         
                                                
                                                                                                            
                                             
                        
                        
                            
                                                                                        
                                Edgar J. Kaiser
                                                                                                                                                    Certified Consultant
                                                         
                            
                         
                                                
    
        Please login with a confirmed email address before reporting spam
     
    
 
                                                Posted:
                            
                                3 years ago                            
                            
                                1 mai 2022, 17:33 UTC−4                            
                        
                        
                                                    In order to verify your methods you may consider to use a simple model with an analytical solution. In 2D axial symmetry this could be a coaxial capacitor.
    -------------------
    Edgar J. Kaiser
emPhys Physical Technology
www.emphys.com                                                 
                                                
                            In order to verify your methods you may consider to use a simple model with an analytical solution. In 2D axial symmetry this could be a coaxial capacitor.